
The internet has a new favorite brain teaser, and it’s as colorful as it is confusing. This “ice cream math” challenge from Gergely Dudás (Dudolf) replaces traditional variables with scoops and cones, forcing you to use algebraic thinking to find the hidden values. While it looks like child’s play, many adults find themselves stuck on the final row. These visual puzzles are excellent for sharpening your mental math and attention to detail, reminding us that sometimes the simplest-looking problems require the most focus.
To find the final answer, we have to break down each row to find the individual value of the cone, the white scoop, and the pink scoop.
Row 1: Three Cones
$\text{Cone} \times \text{Cone} \times \text{Cone} = 27$
Since $3 \times 3 \times 3 = 27$, one Cone = 3.
Row 2: Two Single-Scoop Ice Creams
$(\text{Cone} + \text{White Scoop}) + (\text{Cone} + \text{White Scoop}) = 10$
This means each single-scoop cone equals 5.
Since we know the Cone is 3, then $3 + \text{White Scoop} = 5$.
One White Scoop = 2.
Row 3: Double White Scoop + Pink Scoop
$(\text{Cone} + 2 \text{ White Scoops}) + (\text{Cone} + \text{Pink Scoop}) = 11$
$(3 + 4) + (3 + \text{Pink Scoop}) = 11 \rightarrow 7 + 3 + \text{Pink Scoop} = 11$
One Pink Scoop = 1.
Row 4: The Final Test
$(\text{Cone} + \text{White Scoop}) + \text{Cone} + (\text{Cone} + \text{White Scoop} + 2 \text{ Pink Scoops}) = 15$
$(3 + 2) + 3 + (3 + 2 + 1 + 1) = 15 \rightarrow 5 + 3 + 7 = 15$
Final Values:
Cone = 3
White Scoop = 2
Pink Scoop = 1






